A) 0.5 Hz
B) 1.5 Hz
C) 5 Hz
D) 10 Hz
Correct Answer: C
Solution :
For body to remain in contact \[{{a}_{\max }}=g\] \[\therefore {{\omega }^{2}}A=g\Rightarrow 4{{\pi }^{2}}{{n}^{2}}A=g\] \[\Rightarrow {{n}^{2}}=\frac{g}{4{{\pi }^{2}}A}=\frac{10}{4{{(3.14)}^{2}}0.01}=25\] \[\Rightarrow n=5\ Hz\]
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