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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    The dissociation constant of two acids \[H{{A}_{1}}\] and \[H{{A}_{2}}\] are \[3.14\times {{10}^{-4}}\] and \[1.96\times {{10}^{-5}}\] respectively. The relative strength of the acids will be approximately            [RPMT 2000]

    A)                 1 : 4       

    B)                 4 : 1

    C)                 1 : 16     

    D)                 16 : 1

    Correct Answer: B

    Solution :

                    \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\sqrt{\frac{{{K}_{{{a}_{1}}}}}{{{K}_{{{a}_{2}}}}}}=\sqrt{\frac{3.14\times {{10}^{-4}}}{1.6\times {{10}^{-5}}}}=4:1\]


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