A) 60°
B) 45°
C) 30°
D) 15°
Correct Answer: B
Solution :
\[{{n}_{eff}}={{n}_{0}}\sqrt{1-\left( \frac{80.5\,N}{{{\nu }^{2}}} \right)}=1\sqrt{1-\frac{80.5\times (400\times {{10}^{6}})}{{{(55\times {{10}^{6}})}^{2}}}}\approx 1\] Also \[{{n}_{eff}}=\frac{\sin i}{\sin r}\] Þ \[\sin r=\sin i\] Þ \[r=i=45{}^\circ \]
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