A) \[{{4}^{th}}\]
B) \[{{3}^{rd}}\]
C) \[{{10}^{th}}\]
D) None of these
Correct Answer: C
Solution :
\[{{(1+3x+3{{x}^{2}}+{{x}^{3}})}^{6}}={{\{{{(1+x)}^{3}}\}}^{6}}={{(1+x)}^{18}}\] Hence the middle term is\[{{10}^{th}}\].
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