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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Critical Thinking Solutions

  • question_answer
    Boiling point of chloroform was raised by 0.323 K, when 0.5143 g of anthracene was dissolved in 35 g of chloroform. Molecular mass of anthracene is (\[{{K}_{b}}\] for \[CHC{{l}_{3}}\]= 3.9 kg mol?1)                [Pb PMT 2000]

    A)                 79.42 g/mol          

    B)                 132.32 g/mol

    C)                 177.42 g/mol        

    D)                 242.32 g/mol

    Correct Answer: C

    Solution :

             Here: \[\Delta {{T}_{b}}=0.323K\]            \[w=0.5143g\] weight of Anthracene.            \[W=35g\] weight of chloroform            \[{{K}_{b}}=\] Molal elevation constant\[(3.9\,\,K-Kg/mol)\]            \[m=\frac{{{K}_{b}}\times w\times 1000}{W\times \Delta {{T}_{b}}}=\frac{3.9\times 0.5143\times 1000}{0.323\times 35}\]           \[=177.42g/mol\]


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