A) 110 m/s
B) 55 m/s
C) 550 m/s
D) 660 m/s
Correct Answer: B
Solution :
The area under acceleration time graph gives change in velocity. As acceleration is zero at the end of 11 sec i.e. \[{{v}_{\max }}=\]Area of \[\Delta OAB\] \[=\frac{1}{2}\times 11\times 10=55\ m/s\]You need to login to perform this action.
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