A) \[1.10\,V\]
B) \[0.110\,V\]
C) \[-1.10\,V\]
D) \[-\,0.110\,V\]
Correct Answer: A
Solution :
\[{{E}_{cell}}=E_{cell}^{o}-\frac{0.059}{2}\,\,\log \frac{(Z{{n}^{++}})}{(C{{u}^{++}})}\] \[=1.10-\frac{0.059}{2}\,\,\log \frac{0.1}{0.1}=1.10\,\,V\].You need to login to perform this action.
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