A) 5
B) 4
C) 3
D) 2
Correct Answer: C
Solution :
\[NO_{3}^{-}+4{{H}^{+}}+4{{e}^{-}}\to 2{{H}_{2}}O+NO.\] In this equation all the atoms are balanced. For balancing added \[3{{e}^{-}}\] to \[L.H.S.\] we have, \[NO_{3}^{-}+4{{H}^{+}}+3{{e}^{-}}\to 2{{H}_{2}}O+NO\].You need to login to perform this action.
You will be redirected in
3 sec