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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Critical Thinking Electrochemistry

  • question_answer
    The standard reduction potential \[NaCl\]for the half reactions are as                 \[Zn=Z{{n}^{2+}}+2{{e}^{-}};\,\,{{E}^{o}}=+0.76\,V\]                 \[Fe=F{{e}^{2+}}+2{{e}^{-}};\,\,{{E}^{o}}=+0.41\,V\]                 The EMF for cell reaction \[F{{e}^{2+}}+Zn\,\to \,Z{{n}^{2+}}+Fe\] is [IIT 1988; CBSE PMT 1993, 96; BHU 1995, 2000; CPMT 2000; KCET 2000; AIIMS 2001; Orissa JEE 2002]

    A)                 \[-\,0.35\,V\]    

    B)                 \[+\,0.35\,V\]

    C)                 \[+\,1.17\,V\]   

    D)                 \[-\,1.17\,V\]

    Correct Answer: B

    Solution :

               In this reaction \[F{{e}^{2+}}+\overset{0}{\mathop{Zn}}\,\to \overset{2+}{\mathop{Zn}}\,+\overset{0}{\mathop{Fe}}\,\]                            \[EMF={{E}_{\text{cathode}}}-{{E}_{\text{anode}}}\]\[=-0.41-(-0.76)\]\[EMF=+0.35\]V.


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