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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Critical Thinking Electrochemistry

  • question_answer
    What amount of Cl2 gas liberated at anode, if 1 amp. current is passed for 30 min. from NaCl solution. [BHU 2005]

    A)                 0.66 moles         

    B)                 0.33 moles

    C)                 0.66 g   

    D)                 0.33 g

    Correct Answer: C

    Solution :

               The reaction taking place at anode is                    2Cl? ®   Cl2    +    2e­?                             1 mole     2 ´ 96500 coulomb                    Q = i . t = 1 ´ 30 ´ 60 = 1800 coulomb.                                 The amount of chlorine liberated by passing 1800 coulomb of electric charge       \[=\frac{1\times 1800\times 71}{2\times 96500}=0.66\,\,g\].


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