Calculate \[\Lambda _{HOAc}^{\infty }\] using appropriate molar conductances of the electrolytes listed above at infinite dilution in \[{{H}_{2}}O\] at 25°C [AIEEE 2005]
A) 517.2
B) 552.7
C) 390.7
D) 217.5
Correct Answer: C
Solution :
\[\Lambda _{HOAC}^{\infty }=\Lambda _{NaOAC}^{\infty }+\Lambda _{HCl}^{\infty }-\Lambda _{NaCl}^{\infty }\] \[=91.0+426.2-126.5=390.7\]
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