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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Critical Thinking Chemical Kinetics

  • question_answer
    The rate constant \[({K}')\] of one reaction is double of the rate constant \[({K}'')\] of another reaction. Then the relationship between the corresponding activation energies of the two reactions  (\[{{E}_{a}}^{\prime }\] and  \[{{E}_{a}}^{\prime\prime }\]) will be [MP PET 1994; UPSEAT 2001]

    A)                 \[{{E}_{a}}^{\prime }>{{E}_{a}}^{\prime\prime }\]          

    B)                 \[{{E}_{a}}^{\prime }={{E}_{a}}^{\prime\prime }\]

    C)                 \[{{E}_{a}}^{\prime }<{{E}_{a}}^{\prime\prime }\]          

    D)                 \[{{E}_{a}}^{\prime }=4{{E}_{a}}^{\prime\prime }\]

    Correct Answer: C

    Solution :

                    As \[{{K}^{'}}>{{K}^{''}},E_{a}^{'}<E_{a}^{''}\] (Greater the rate constant, less is the activation energy).


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