A) \[-\frac{d[{{H}_{2}}]}{dt}=-\frac{d[{{I}_{2}}]}{dt}=+\frac{1}{2}\frac{d[HI]}{dt}\]
B) \[\frac{d[{{H}_{2}}]}{dt}=\frac{d[HI]}{dt}=\frac{1}{2}\frac{d[HI]}{dt}\]
C) \[\frac{1}{2}\frac{d[{{H}_{2}}]}{dt}=\frac{1}{2}\frac{d[{{I}_{2}}]}{dt}=-\frac{d[HI]}{dt}\]
D) \[-2\frac{d[{{H}_{2}}]}{dt}=-2\frac{d[{{I}_{2}}]}{dt}=+\frac{d[HI]}{dt}\]
Correct Answer: A
Solution :
Concentration of reactants decreases while concentration of product increases.You need to login to perform this action.
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