JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Critical Thinking Chemical Kinetics

  • question_answer
    The integrated rate equation is \[Rt=\log \ {{C}_{0}}-\log {{C}_{t}}\]. The straight line graph is obtained by plotting                [AIEEE 2002]

    A)                 \[\text{time}\ \text{v/s}\ \text{log}{{\text{C}}_{\text{t}}}\]       

    B)                 \[\frac{1}{\text{time}}\text{v}/\text{s}\ {{\text{C}}_{\text{t}}}\]

    C)                 \[\text{time}\ \text{v}/\text{s}\ {{\text{C}}_{\text{t}}}\]             

    D)                 \[\frac{1}{\text{time}}\text{v}/\text{s}\ \frac{1}{{{\text{C}}_{\text{t}}}}\]

    Correct Answer: A

    Solution :

                    It is similar to \[y=mx+c\]


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