A) \[-\frac{\Delta [{{I}_{2}}]}{\Delta t}=-\frac{\Delta [{{H}_{2}}]}{\Delta t}=\frac{1}{2}\frac{\Delta [HI]}{\Delta t}\]
B) \[\frac{\Delta [{{I}_{2}}]}{\Delta t}=\frac{\Delta [{{H}_{2}}]}{\Delta t}=\frac{\Delta [HI]}{2\Delta t}\]
C) \[\frac{\Delta [{{H}_{2}}]}{\Delta t}=\frac{1}{2}\frac{\Delta [{{I}_{2}}]}{\Delta t}=-\frac{\Delta [HI]}{\Delta t}\]
D) None of these
Correct Answer: A
Solution :
For the given reaction : \[-\frac{\Delta [{{I}_{2}}]}{\Delta t}=-\frac{\Delta [{{H}_{2}}]}{\Delta t}=\frac{1}{2}\frac{\Delta [HI]}{\Delta t}\]You need to login to perform this action.
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