A) \[CHC{{l}_{3}}\]
B) \[C{{l}_{3}}CCHO\]
C) \[CC{{l}_{4}}\]
D) \[ClC{{H}_{2}}C{{H}_{2}}Cl\]
Correct Answer: B
Solution :
\[CC{{l}_{3}}-CHO+{{H}_{2}}O\to \underset{(\text{Chloral}\,\,\text{hydrate})}{\mathop{CC{{l}_{3}}.CHO.{{H}_{2}}O}}\,\to \]\[CC{{l}_{3}}.CH<\begin{matrix} OH \\ {} \\ OH \\ \end{matrix}\]
You need to login to perform this action.
You will be redirected in
3 sec
