A) \[N{{O}_{2}}\]
B) Kr
C) COS
D) \[S{{O}_{2}}\]
Correct Answer: C
Solution :
\[d=\frac{M}{V}\] \[\Rightarrow \] \[M=d\times V\] \[M=2.68\times 22.4\] at N.T.P. \[\left( \because V=22.41 \right)\] \[M=60.03\,gm\] m. wt of \[COS=12+16+32=60\]You need to login to perform this action.
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