A) \[f(x)\]is continuous at \[x=2\]
B) \[f(x)\]is discontinuous at \[x=2\]
C) \[\underset{x\to 2}{\mathop{\lim }}\,f(x)=1\]
D) None of these
Correct Answer: B
Solution :
\[\underset{x\to 2-}{\mathop{\lim }}\,f(x)=\frac{1}{2}\] and \[\underset{x\to 2+}{\mathop{\lim }}\,f(x)=\frac{1}{2}\] and\[f(2)=1.\]
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