question_answer

Following are the steps of construction of a \[\Delta ABC\]in which AB = 5 cm, \[\angle A={{30}^{o}}\] and AC - BC = 2.5 cm. Arrange them and select the CORRECT option.

(i) Draw \[\angle BAX={{30}^{o}}\]

(ii) Draw the perpendicular bisector of BD which cuts AX at C.

(iii) Draw AB = 5 cm

(iv) Join BD

(v)  Join BC to obtain the required triangle ABC

(vi) From ray AX, cut off line segment AD = AC-BC= 2.5 cm

A) (a\[(i)\to (iii)\to (iv)\to (v)\to (vi)\to (ii)\]

B) \[(iii)\to (i)\to (vi)\to (iv)\to (ii)\to (v)\]

C) \[(iii)\to (i)\to (ii)\to (v)\to (iv)\to (vi)\]

D) \[(iii)\to (ii)\to (iv)\to (i)\to (vi)\to (v)\]