A) 10 N
B) 100 N
C) 1.0 N
D) 0.1 N
Correct Answer: A
Solution :
During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant) \[\therefore \]\[F=\frac{\text{Change in horizontal momentum }}{\text{Time of contact}}\] \[=\frac{2P\cos \theta }{0.1}=\frac{2mv\cos \theta }{0.1}\] \[=\frac{2\times 0.1\times 10\times \cos 60{}^\circ }{0.1}\]\[=10\ N\]You need to login to perform this action.
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