A) 9 Ns
B) Zero
C) 0.9 Ns
D) 1.8 Ns
Correct Answer: C
Solution :
\[F=600-2\times {{10}^{5}}t=0\] Þ \[t=3\times {{10}^{-3}}\,\sec \] Impulse \[I=\int_{0}^{t}{F\,dt}=\int_{0}^{3\times {{10}^{-3}}}{(600-2\times {{10}^{3}}t)dt}\] \[=[600t-{{10}^{5}}{{t}^{2}}]_{0}^{3\times {{10}^{-3}}}=0.9\,N\times \sec \]You need to login to perform this action.
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