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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Conservation of Linear Momentum and Impulse

  • question_answer
    A bullet is fired from a gun. The force on the bullet is given by \[F=600-2\times {{10}^{5}}t\], where F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet                          [CBSE PMT 1998]

    A)             9 Ns    

    B)             Zero

    C)             0.9 Ns 

    D)             1.8 Ns

    Correct Answer: C

    Solution :

                    \[F=600-2\times {{10}^{5}}t=0\] Þ \[t=3\times {{10}^{-3}}\,\sec \] Impulse \[I=\int_{0}^{t}{F\,dt}=\int_{0}^{3\times {{10}^{-3}}}{(600-2\times {{10}^{3}}t)dt}\]             \[=[600t-{{10}^{5}}{{t}^{2}}]_{0}^{3\times {{10}^{-3}}}=0.9\,N\times \sec \]


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