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JEE Main & Advanced Mathematics Conic Sections Question Bank Conic section - General

  • question_answer
    Angle of intersection of the curves \[r=\sin \theta +\cos \theta \] and \[r=2\sin \theta \] is equal to        [UPSEAT 2004]

    A)            \[\frac{\pi }{2}\]                 

    B)            \[\frac{\pi }{3}\]

    C)            \[\frac{\pi }{4}\]                 

    D)            None of these

    Correct Answer: C

    Solution :

               Here \[r=\sin \theta +\cos \theta \] and \[r=2\sin \theta \]                    \[\therefore \] \[2\sin \theta =\sin \theta +\cos \theta \Rightarrow \sin \theta =\cos \theta \]                    \[\Rightarrow \] \[\tan \theta =1\Rightarrow \theta =\frac{\pi }{4}\].


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