A) \[{{({{x}^{2}}y)}^{2/3}}+{{(x{{y}^{2}})}^{2/3}}=1\]
B) \[{{x}^{2}}-{{y}^{2}}=4xy\]
C) \[{{({{x}^{2}}-{{y}^{2}})}^{2}}=16xy\]
D) \[{{x}^{2}}-{{y}^{2}}=6xy\]
Correct Answer: C
Solution :
Trick: Put the value of (x, y) \[\equiv \] (tan\[\theta +\sin \theta ,\,\tan \theta -\sin \theta )\] in option (c), which satisfies the equation.
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