JEE Main & Advanced Mathematics Conic Sections Question Bank Conic section - General

  • question_answer
    The centre of \[14{{x}^{2}}-4xy+11{{y}^{2}}-44x-58y+71=0\] [BIT Ranchi 1986]

    A)            (2, 3)                                        

    B)            (2, ? 3)

    C)            (? 2, 3)                                    

    D)            (? 2, ? 3)

    Correct Answer: A

    Solution :

               Use formula of centre of conic i.e., \[\left( \frac{hf-bg}{ab-{{h}^{2}}},\,\frac{gh-af}{ab-{{h}^{2}}} \right)\].


You need to login to perform this action.
You will be redirected in 3 sec spinner