A) \[{{x}^{2}}-{{y}^{2}}=1\]
B) \[xy=1\]
C) \[2xy-4x+4y+1=0\]
D) \[2xy+4x-4y-1=0\]
Correct Answer: C
Solution :
Let P (x, y) be any point on the conic. Then \[\sqrt{{{(x-1)}^{2}}+{{(y+1)}^{2}}}=\sqrt{2}\left( \frac{x-y+1}{\sqrt{2}} \right)\], [Using \[SP=e.PM]\] \[\Rightarrow 2xy-4x+4y+1=0\].You need to login to perform this action.
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