7th Class Mathematics Congruence of Triangles Question Bank Congruence of Triangles

  • question_answer
    In the given figure of a hockey field, \[\Delta ABC\] is congruent to \[\Delta PQR\]. If \[PC=200\text{ }cm,\]and \[AP=CR\] then what is the length of AR?

    A)  150 metres     

    B)  300 metres     

    C)  470 metres                 

    D)  500 metres

    Correct Answer: B

    Solution :

    (b): \[AC=\sqrt{A{{B}^{2}}+B{{C}^{2}}}=\sqrt{A{{B}^{2}}+Q{{R}^{2}}}\] (Since\[BC=QR\] by congruency) \[=\sqrt{{{70}^{2}}+{{240}^{2}}}=250m;\] \[AP=AC-PC=250-200=50\] Also, \[CR=AP=50\] \[\Rightarrow AR=AC+CR\] \[=250+50\] \[=300\]


You need to login to perform this action.
You will be redirected in 3 sec spinner