A) 1
B) 2
C) 8
D) 16
Correct Answer: A
Solution :
\[\frac{dQ}{dt}=\frac{K(\pi {{r}^{2}})d\theta }{dl}\]Þ \[\frac{{{\left( \frac{dQ}{dt} \right)}_{s}}}{{{\left( \frac{dQ}{dt} \right)}_{l}}}=\frac{{{K}_{s}}\times r_{s}^{2}\times {{l}_{l}}}{{{K}_{l}}\times r_{l}^{2}\times {{l}_{s}}}\] = \[\frac{1}{2}\times \frac{1}{4}\times \frac{2}{1}\] Þ \[{{\left( \frac{dQ}{dt} \right)}_{s}}=\frac{{{\left( \frac{dQ}{dt} \right)}_{l}}}{4}=\frac{4}{4}=1\]
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