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JEE Main & Advanced Mathematics Probability Question Bank Conditional probability bayes theorem

  • question_answer
    If the events A and B are mutually exclusive, then \[P\left( \frac{A}{B} \right)=\]

    A)                 0             

    B)                 1

    C)                 \[\frac{P\,(A\cap B)}{P\,(A)}\]             

    D)                 \[\frac{P\,(A\cap B)}{P\,(B)}\]

    Correct Answer: A

    Solution :

                      \[P\left( \frac{A}{B} \right)=\frac{P(A\cap B)}{P(B)}\]            Since \[A\] and \[B\] are mutually exclusive.                 So, \[P(A\cap B)=0\]. Hence \[P\left( \frac{A}{B} \right)=\frac{0}{P(B)}=0\].


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