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JEE Main & Advanced Mathematics Probability Question Bank Conditional probability bayes theorem

  • question_answer
    If A and B are two events such that \[P\,(A)=\frac{3}{8},\,\] \[P\,(B)=\frac{5}{8}\] and \[P\,(A\cup B)=\frac{3}{4},\] then\[P\,\left( \frac{A}{B} \right)=\]

    A)                 \[\frac{2}{5}\]

    B)                 \[\frac{2}{3}\]

    C)                 \[\frac{3}{5}\]       

    D)                 None of these

    Correct Answer: A

    Solution :

                    \[P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{(3/8)+(5/8)-(3/4)}{(5/8)}=\frac{2}{5}\].


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