A) 12%
B) 16.66%
C) 18.67%
D) 19.25%
Correct Answer: B
Solution :
(b): Let rate of interest be 'r' sum invested = P \[\therefore 600=P\left( 1+\frac{6r}{100} \right).......1\] and \[800=P\left( 1+\frac{10r}{100} \right).......2\] Dividing, \[\frac{600}{800}=\frac{1+\frac{6r}{100}}{1+\frac{10r}{100}}\] \[\Rightarrow \frac{6}{8}=\frac{3}{4}=\frac{1+\frac{6r}{100}}{1+\frac{10r}{100}}\] Cross multiplying, \[3+\frac{30r}{100}=4+\frac{24r}{100}\] \[\frac{6r}{100}=1\] \[r=\frac{100}{6}=16.66%\]You need to login to perform this action.
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