JEE Main & Advanced Physics Communication System / संचार तंत्र Question Bank Communication

  • question_answer
    An oscillator is producing FM waves of frequency 2 kHz with a variation of 10 kHz. What is the modulating index [DCE 2004]

    A)            0.20                                          

    B)            5.0

    C)            0.67                                          

    D)            1.5

    Correct Answer: B

    Solution :

               The formula for modulating index is given by \[{{m}_{f}}=\frac{\delta }{{{\nu }_{m}}}=\frac{\text{Frequency  variation }}{\text{Modulating frequency}}=\frac{10\times {{10}^{3}}}{2\times {{10}^{3}}}=5\]


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