JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer Solubility product for salt \[A{{B}_{2}}\] is \[4\times {{10}^{-12}}\]. Calculate solubility    [RPET 2003]

    A)                 \[1\times {{10}^{-3}}gm\,\,mol\,/\,litre\]

    B)                 \[1\times {{10}^{-5}}gm\,\,mol\,/\,litre\]

    C)                 \[1\times {{10}^{-4}}gm\,\,mol\,/\,litre\]

    D)                 \[1\times {{10}^{-2}}gm\,\,mol\,/\,litre\]

    Correct Answer: C

    Solution :

               \[A{{B}_{2}}\]⇌\[\underset{(S)\,}{\mathop{{{A}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2{{B}^{-}}}}\,\]                    \[{{K}_{sp}}=4{{S}^{3}}\]                                 \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}\] \[=1\times {{10}^{-4}}\,\,gm.\,mol/litre\]


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