JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer
    The solubility of \[CaC{{O}_{3}}\]in water is \[3.05\times {{10}^{-4}}moles/litre.\] Its solubility product will be     [MP PMT 1997]

    A)                 \[3.05\times {{10}^{-4}}\]            

    B)                 10

    C)                 \[6.1\times {{10}^{-4}}\]              

    D)                 \[9.3\times {{10}^{-8}}\]

    Correct Answer: D

    Solution :

    \[\underset{S}{\mathop{CaC{{O}_{3}}}}\,\]⇌\[\underset{S}{\mathop{C{{a}^{++}}}}\,+\underset{S}{\mathop{CO_{3}^{-\,-}}}\,\]                    Solubility product of \[CaC{{O}_{3}}\]                    \[{{K}_{sp}}={{S}^{2}}\]; \[S=\sqrt{{{K}_{sp}}}\]                    It is a binary electrolyte.                                 \[{{S}^{2}}={{K}_{sp}}\]; \[{{(3.05\times {{10}^{-4}})}^{2}}={{K}_{sp}}\];\[{{K}_{sp}}=9.3\times {{10}^{-8}}\]


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