JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer At 298 K, the solubility of \[PbC{{l}_{2}}\] is \[2\times {{10}^{-2}}mol/lit\], then \[{{k}_{sp}}=\]                                   [RPMT 2002]

    A)                 \[1\times {{10}^{-7}}\]  

    B)                 \[3.2\times {{10}^{-7}}\]

    C)                 \[1\times {{10}^{-5}}\]  

    D)                 \[3.2\times {{10}^{-5}}\]

    Correct Answer: D

    Solution :

           \[PbC{{l}_{2}}\]⇌\[\underset{(S)\,\,}{\mathop{P{{b}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2C{{l}^{-}}}}\,\]                                 \[{{K}_{sp}}=4{{S}^{3}}=4\times {{(2\times {{10}^{-2}})}^{3}}=3.2\times {{10}^{-5}}\]


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