JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility product of a sparingly soluble salt \[AB\] at room temperature is \[1.21\times {{10}^{-6}}\]. Its molar solubility is [CPMT 1987; MP PET 2001]

    A)                 \[1.21\times {{10}^{-6}}\]            

    B)                 \[1.21\times {{10}^{-3}}\]

    C)                 \[1.1\times {{10}^{-4}}\]              

    D)                 \[1.1\times {{10}^{-4}}\]

    Correct Answer: D

    Solution :

               AB is a binary electrolyte.                    \[S=\sqrt{{{K}_{sp}}}=\sqrt{1.21\times {{10}^{-6}}}=1.1\times {{10}^{-3}}M\]

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