JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer If the solubility product \[{{K}_{sp}}\] of a sparingly soluble salt \[M{{X}_{2}}\] at \[25{}^\circ C\] is \[1.0\times {{10}^{-11}}\], the solubility of the salt in mole litre?1 at this temperature will be                [RPMT 2000]

    A)                 \[2.46\times {{10}^{14}}\]           

    B)                 \[1.36\times {{10}^{-4}}\]

    C)                 \[2.60\times {{10}^{-7}}\]            

    D)                 \[1.20\times {{10}^{-10}}\]

    Correct Answer: B

    Solution :

               \[M{{X}_{2}}\]⇌ \[\underset{(S)\,\,\,}{\mathop{{{M}^{+}}}}\,+\underset{{{(2S)}^{2}}\,\,}{\mathop{2{{X}^{-}}}}\,\]; \[{{K}_{sp}}=4{{S}^{3}}\]                                 \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{1\times {{10}^{-11}}}{4}}=1.35\times {{10}^{-4}}\]


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