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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer
    The solubility product of \[BaS{{O}_{4}}\] is \[1.5\times {{10}^{-9}}.\] The precipitation in a 0.01 \[M\,\,B{{a}^{2+}}\]solution will start, on adding \[{{H}_{2}}S{{O}_{4}}\] of concentration       [CPMT 1988]

    A)                 \[{{10}^{-9}}M\]              

    B)                 \[{{10}^{-8}}M\]

    C)                 \[{{10}^{-7}}M\]              

    D)                 \[{{10}^{-6}}M\]

    Correct Answer: C

    Solution :

               \[{{K}_{sp}}\] of  \[BaS{{O}_{4}}=1.5\times {{10}^{-9}}\]; \[B{{a}^{++}}=0.01M\]                                 \[SO_{4}^{-\,-}=\frac{1.5\times {{10}^{-9}}}{0.01}=1.5\times {{10}^{-7}}\]


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