JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer Solubility product of a sulphide MS is \[3\times {{10}^{-25}}\]and that of another sulphide NS is \[4\times {{10}^{-40}}\]. In ammoniacal solution [NCERT 1981]

    A)                 Only NS gets precipitated

    B)                 Only MS gets precipitated

    C)                 No sulphide precipitates

    D)                 Both sulphides precipitate

    Correct Answer: D

    Solution :

                    The concentration of \[{{S}^{2-}}\]ions in group II is lowered by maintaining acidic medium in the presence of \[N{{H}_{4}}Cl\]. The ionization of \[{{H}_{2}}S\] is supressed due to common ion effect. So the ionic product is less than solubility product.


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