JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer The solubility of \[Ca{{F}_{2}}\] is\[2\times {{10}^{-4}}\,moles/litre.\] Its solubilily product \[({{K}_{sp}})\] is        [NCERT 1981; BHU 1983, 86; MP PET 1992; CBSE PMT 1999]

    A)                 \[2.0\times {{10}^{-4}}\]              

    B)                 \[4.0\times {{10}^{-3}}\]

    C)                 \[8.0\times {{10}^{-12}}\]            

    D)                 \[3.2\times {{10}^{-11}}\]

    Correct Answer: D

    Solution :

                    \[{{K}_{sp}}\]for \[Ca{{F}_{2}}=4{{s}^{3}}\] \[=4\times {{[2\times {{10}^{-4}}]}^{3}}=3.2\times {{10}^{-11}}\].

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