JEE Main & Advanced Chemistry Equilibrium Question Bank Common ion effect, Isohydric solutions, Solubility product, Ionic product of water and salt hydrolysis

  • question_answer Solubility product of \[AgCl\] is \[1\times {{10}^{-6}}\] at 298 K. Its solubility in mole \[litr{{e}^{-1}}\] would be                    [Pb.CET 2001]

    A)                 \[1\times {{10}^{-6}}mol/litre\]

    B)                 \[1\times {{10}^{-3}}mol/litre\]

    C)                 \[1\times {{10}^{-12}}mol/litre\]

    D)                 None of these

    Correct Answer: B

    Solution :

                For \[AgCl\to \underset{x}{\mathop{A{{g}^{+}}}}\,+\underset{x}{\mathop{C{{l}^{-}}}}\,\]                                 \[{{K}_{sp}}={{x}^{2}}\]; \[x=\sqrt{{{K}_{sp}}}\], \[\sqrt{1\times {{10}^{-6}}}=1\times {{10}^{-3}}mole/litre\].

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