A) \[Cu+HgC{{l}_{2}}\to CuC{{l}_{2}}+Hg\]
B) \[2HN{{O}_{3}}+3{{H}_{2}}S\to 3S+4{{H}_{2}}O+2NO\]
C) \[2Mg+C{{O}_{2}}\to 2MgO+C\]
D) \[Cu+CuC{{l}_{2}}\to C{{u}_{2}}C{{l}_{2}}\] (in presence of excess of \[HCl\])
Correct Answer: B
Solution :
\[2HN{{O}_{3}}+3{{H}_{2}}S\to \underset{(Sol)}{\mathop{3S}}\,+4{{H}_{2}}O+2NO\]
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