A) \[\log \frac{{{K}_{2}}}{{{K}_{1}}}=\frac{{{E}_{a}}}{2.303R}\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right]\]
B) \[\log \frac{{{K}_{1}}}{{{K}_{2}}}=-\frac{{{E}_{a}}}{2.303R}\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right]\]
C) \[\log \frac{{{K}_{1}}}{{{K}_{2}}}=-\frac{{{E}_{a}}}{2.303R}\left[ \frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}{{T}_{2}}} \right]\]
D) None of these
Correct Answer: A
Solution :
It is modified form of Arrhenius equation.You need to login to perform this action.
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