A) Glucose \[>\,NaCl\,\,>\,\,BaC{{l}_{2}}\]
B) \[NaCl\,\,>\,\,BaC{{l}_{2}}\,\,>\] Glucose
C) \[BaC{{l}_{2}}\,\,>\,\,NaCl\,\,>\] Glucose
D) Glucose \[>\,\,BaC{{l}_{2}}\,\,>\,\,NaCl\]
Correct Answer: C
Solution :
\[BaC{{l}_{2}}\] Þ \[B{{a}^{2+}}+2C{{l}^{-}}=3\]ion \[NaCl\] Þ \[N{{a}^{+}}+C{{l}^{-}}=2\]ion Glucose Þ No ionisation \ \[BaC{{l}_{2}}>NaCl>\text{Glucose}\]You need to login to perform this action.
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