A) \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]
B) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
C) \[KI\]
D) \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\]
Correct Answer: A
Solution :
\[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\] gives maximum ion hence its gives lowest freezing point.
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