A) \[\text{AC}+\text{AD}=\text{BD}+\text{CD}\]
B) \[\text{AB}+\text{CD}=\text{BC}+\text{AD}\]
C) \[\text{AB}+\text{CD}=\text{AC}+\text{BD}\]
D) \[~\text{AC}+\text{AD}=\text{BC}+\text{AB}\]
Correct Answer: B
Solution :
Given sides of a quadrilateral ABCD are tangential to a circle. \[\therefore \] \[\text{7}\times \text{13}+\text{13}\]You need to login to perform this action.
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