A) \[{{50}^{o}}\]
B) \[{{80}^{o}}\]
C) \[{{90}^{o}}\]
D) \[{{40}^{o}}\]
Correct Answer: B
Solution :
Since, angle subtended by an arc at centre is double the angle subtended by it on the remaining part of the circle. \[\therefore \]\[\angle AOB=2\angle ACB=2\times {{40}^{o}}={{80}^{o}}\]
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