A) \[{{150}^{o}}\]
B) \[{{75}^{o}}\]
C) \[{{62}^{o}}\]
D) \[{{60}^{o}}\]
Correct Answer: B
Solution :
Given, \[\angle AOC={{55}^{o}},\angle BOC={{155}^{o}}\] reflex \[\angle AOB=\angle AOC\,+\,\angle BOC={{55}^{o}}+{{155}^{o}}={{210}^{o}}\] \[\therefore \]\[\angle AOB={{360}^{o}}-{{210}^{o}}={{150}^{o}}\] Since, angle subtended by arc at center is double the angle subtended by it on the remaining part of the circle. \[\therefore \] \[\angle ACB=\frac{1}{2}\angle AOB={{75}^{o}}\]
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