A) \[AB+AD=CB+CD\]
B) \[AB:CD=AD:BC\]
C) \[AB+CD=AD+BC\]
D) \[AB:AD=CB:CD\]
Correct Answer: C
Solution :
(c):- We know that, two tangents drawn from an external point to a circle are of equal lengths. \[AP=AS\Rightarrow BP=BQ\] \[CR=CQ\Rightarrow DR=DS\] \[\Rightarrow \] \[AP+BP+CR+DR=AS+BQ+CQ+DS\] \[\therefore \] \[AB+CD=AD+BC\]You need to login to perform this action.
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