A) \[{{s}^{2}}\]
B) \[ab+bc+ca\]
C) \[\Delta \]
D) None of these
Correct Answer: C
Solution :
\[\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=\frac{1}{2R}\]\[\Rightarrow \sin A=\frac{a}{2R}\] etc. Therefore\[2{{R}^{2}}\sin A\sin B\sin C=\]\[2{{R}^{2}}\frac{a}{2R}\,.\,\frac{b}{2R}.\frac{c}{2R}\] \[=\frac{abc}{4R}=\Delta \].
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